如图,△ABC的角平分线BO、CO相交于点O,∠A=120°,则∠BOC=()
A.150° | B.140° | C.130° | D.120° |
如图,已知AB∥DE,∠ABC=80°,∠CDE=140°,则∠C=()
A.20° | B.30° | C.40° | D.50° |
如图,小明将一张三角形纸片(△ABC),沿着DE折叠(点D、E分别在边AB、AC上),并使点A与点A′重合,若∠A=70°,则∠1+∠2的度数为()
A.140° B.130° C.110° D.70°
在△ABC中,∠A+∠B=120°,则∠C=()
A.60° | B.45° | C.30° | D.50° |
△ABC中,∠A=50°,∠B=60°,则∠C=()
A.50° | B.60° | C.70° | D.80° |