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题文

右图所示装置I是一种可充电电池,装置II为电解池。离子交换膜只允许Na通过,充放电的化学方程式为2Na2S2+NaBr3 Na2S4+3NaBr。闭合开关K时,b极附近先变红色。下列说法正确的是

A.负极反应为4Na4e=4Na
B.当有0.01 mol Na通过离子交换膜时,
b电极上析出标准状况下的气体112 mL
C.闭合K后,b电极附近的pH变小
D.闭合K后,a电极上有气体产生
科目 化学   题型 选择题   难度 较易
知识点: 探究电解池作用
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