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题文

将11.9g由Mg、Al、Fe组成的合金溶于足量的NaOH溶液中,合金质量减少了2.7g。另取等质量的合金溶于过量稀硝酸中,生成了6.72LNO(标准状况下),向反应后的溶液中加入适量NaOH溶液恰好使Mg2+、Al3+、Fe3+完全转化为沉淀,则沉淀的质量为

A.22.1g B.27.2g C.30g D.30.2g
科目 化学   题型 选择题   难度 中等
知识点: 探究物质的组成或测量物质的含量
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