已知：在△ABC中，∠C=90°，AC=20cm，BC=15cm．以BC边为轴把这个直角三角形旋转一周．求所得的旋转体的表面积．
直接写得数．×= 0×=÷=÷4= 12÷= 0.3×=×÷×= 0×+=
直接写出得数 21×=÷2=×=÷=÷= 12÷= 1÷=×0=
直接写得数． 20×=÷=×=÷6=×12=×=
直接写得数．×=﹣=×=×=÷=÷=÷=÷=
直接写得数÷=×=﹣=×1.4= 12×= 24×=+= 0÷=
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