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题文

已知:P4(g)+6Cl2(g)=4PCl3(g) ΔH=a kJ·mol-1,P4(g)+10Cl2(g)=4PCl5(g) ΔH=b kJ·mol-1,并知形成或拆开1 mol化学键放出或吸收的能量称为该化学键的键能。P4具有正四面体结构,PCl5中P-Cl键的键能为c kJ·mol-1,PCl3中P-Cl键的键能为1.2c kJ·mol-1。下列叙述正确的是(  )

A.P-P键的键能大于P-Cl键的键能
B.可求Cl2(g)+PCl3(g)=PCl5(s)的反应热ΔH
C.Cl-Cl键的键能为(b-a+5.6c)/4 kJ·mol-1
D.P-P键的键能为(5a-3b+12c)/8 kJ·mol-1
科目 化学   题型 选择题   难度 中等
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